Question

in ∆ ABC , AB=AC and angleB=50° then angleC is _______​

Answer 1

Answer:

According to the question, Δ ABC, AB = AC and ∠B = 50°. Since, BC = AB Δ ABC is an isosceles triangle. Let, ∠C = ∠A = x ∠B = 80° (given) We know that, Using angle sum property, Sum of interior angles of a triangle should be = 180o ∠A + ∠B + ∠C = 180° ⇒ x + 80° + x = 180° ⇒ 2x = 180° – 80° ⇒ 2x = 100° ⇒ x = 50° Therefore, ∠C = ∠A = 50°Read more on Sarthaks.com - https://www.sarthaks.com/870277/in-abc-ab-ac-and-b-50-then-c-is-equal-to-a-40-b-50-c-80-d-130

Answer 2

Answer:

angle C = angle B = 50° ( angle opposite to equal sides are equal)