Question

In ΔABC, AB = AC and ∠B = 65°, then ∠A = ____° ​

Answer 1

Answer:

Since, AB = AC, therefore, ∠B=∠C

By angle sum property of triangle,

∠A+∠B+∠C=180o

70o+2∠B=180o

2∠B=110o

∠B=55o

Hence, ∠B=∠C=55o

Answer 2

$\huge\underline \mathfrak\orange{Answer}$

In $ΔABC, AB = AC$

$=> ∠ABC = ∠ACB$

$∴ ∠ACB = 65°$

Let $∠A$ be $x°$

Now, $∠A + ∠B + ∠C = 180°$

$=> x + 65° + 65° = 180°$

$=> x = 180° - 130°$

$=> 50$

∴ $∠A = 50°$