Math, asked by qwer5179, 5 days ago

In ∆ ABC, AB = AC and D is the mid-point of BC, show by suitable congruence
condition that ∆ABD ≅ ∆ ACD.

Answers

Answered by geetadeshwal

4

Answer:

AB=BC. (given)

AD=AD. (common)

BD=DC. (D is midpoint of BC)

by SSS,∆ABD ≈ ∆ACD

Step-by-step explanation:

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