In ∆ABC ,AB =AC and the side BC is extended up to the point E.If ∠ACE = 115^ 0 ,then ∠ABC=?
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In △ABC,
∠ACD+∠ACB=180 (Linear pair)
115+∠ACB=180
∠ACB=180−115=65
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Now, since, AC=AB
∠ABC=∠ACB=65
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(Isosceles triangle property)
Sum of angles of triangle = 180
∠BAC+∠ABC+∠ACB=180
∠BAC+65+65=180
∠BAC=50
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Step-by-step explanation:
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