In ΔABC, AB=AC , angle A = (5x+20)° and each of the base angle is 2/5th of angle A. Find the measure of angle A.
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Answered by
32
A + B + C = 180°
A = (5x+20)°
B = C (Angles opposite to equal sides are equal)
and,
Now,
(5x+20)+(2x+8)+(2x+8) = 180
5x+20+2x+8+2x+8 = 180
9x+36 = 180
9x = 144
x = 144/9
x = 16
Measure of angle A.
(5×16)+20
80+20
100°
So, Measure of angle A is 100°.
★PLZ MÅRK ÏT THE BRAINLIEST ANSWER AND DROP A ♥
A = (5x+20)°
B = C (Angles opposite to equal sides are equal)
and,
Now,
(5x+20)+(2x+8)+(2x+8) = 180
5x+20+2x+8+2x+8 = 180
9x+36 = 180
9x = 144
x = 144/9
x = 16
Measure of angle A.
(5×16)+20
80+20
100°
So, Measure of angle A is 100°.
★PLZ MÅRK ÏT THE BRAINLIEST ANSWER AND DROP A ♥
pakhi6:
9th
Answered by
5
Answer:
Step-by-step explanation:A + B + C = 180°
A = (5x+20)°
B = C (Angles opposite to equal sides are equal)
and,
Now,
(5x+20)+(2x+8)+(2x+8) = 180
5x+20+2x+8+2x+8 = 180
9x+36 = 180
9x = 144
x = 144/9
x = 16
Measure of angle A.
(5×16)+20
80+20
100°
So, Measure of angle A is 100°.
★PLZ MÅRK ÏT THE BRAINLIEST ANSWER AND DROP A ♥
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