Question

In ∆ABC, AB=AC, angleA = (5x + 20°) and angle B=1/4
of angleA. Find the measure of angle A.
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Answer 1

Step-by-step explanation:

hope it helps you solving:-)

PLZ mark as Branliest

Answer 2

Answer:

120°

Step-by-step explanation:

Given

               ABC is a Δ

               AB=AC

      ∴ ΔABC is an isosceles Δ

and ∠B = ∠C

         ∠A = (5x+ 20°)

      ∴ ∠B = ∠C = 1/4 ( 5x + 20°)

                         = (5x + 20°)/ 4

A/ Q

         ∠A + ∠B + ∠C = 180°  ( Angle sum property of Δ)

      (5x + 20°) + (5x + 20°)/ 4 +(5x + 20°)/ 4 = 180

      ( 25x + 100° + 5x + 20° + 5x + 20° )/ 4 = 180

      30x  +  140° = 180 × 4

      30x = 720 - 120

       x = 600/ 30

       x =  20

   

∴∠A = [( 5×20)+20]

       = 100 + 20

      = 120°