Question

In ∆ABC,AB/AC=BD/DC,angle B=70⁰,angle C=50⁰.find angle BAD​

Answer 1

Step-by-step explanation:

We have, if a line through one vertex of a triangle divides the opposite side in the ratio of the other two sides, then the line bisects the angle at the vertex. ∴ ∠1 = ∠2 In ΔABC ∠A + ∠B + ∠C = 180° ⇒ ∠A + 70 ° + 50° = 180° [∵ ∠B = 70° and ∠C = 50°] ⇒ ∠A = 180° − 120° = 60° ⇒ ∠1 + ∠2 = 60° ⇒ ∠1 + ∠1 = 60° [∵ ∠1 = ∠2] ⇒ 2∠1 = 60° ⇒ ∠1 = 30° ∴ ∠BAD = 30°Read more on Sarthaks.com - https://www.sarthaks.com/33555/in-fig-4-58-abc-is-a-triangle-such-that-ab-ac-bd-dc-b-70-c-50-find-bad

Answer 2

Answer:

The value of angle BAD is 30 degree.