Question

In ∆ABC , AB = AC , D is the midpoint of BC. Show by SSS criterion that ∆ABC = ∆ACD​

Answer 1

Answer:

there is a problem in your qs it seems TriangleABC does not equal to tiiangleACD. I think itsABD=ACD.

In that case    

Proof_ Triangle ABD and Triangle ACD

AB=AC(Given)

BD=DC( Its given that D is the centre of the arm BC)

AD is the common side

Therefore three sides of the tiangles are equal. therefore these triangles are congruent

Step-by-step explanation:

Thank you. Hope this helps you