In ∆ABC,AB=AC,if angle BAC=70°,then find the value of angle ABC
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Answered by
1
Answer:
may be my answer help's you
Step-by-step explanation:
Given, AB = AC, ∠B=70
∠B=∠C=70
∘
(Isosceles triangle property)
Sum of angles,
∠A+∠B+∠C=180
∠A+70+70=180
∠A=40∘
Answered by
2
Answer:
ABC =180
BAC=70
AB=AC
A+B+C = 180
70+B+C= 180
B + C = 180 - 70
B + C =110
B=55
C=55
B Angel is 55°
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