Math, asked by bharathisunkari8, 21 days ago

In ∆ABC,AB=AC,O is a point on BC such that BO=CO and OD is perpendicular to AB and OE is perpendicular to AC. if angle BOD=30⁰ then measure of angle AOE is​

Answers

Answered by shruti5886
0

Answer:

angel AOD = 60 DEGREE

Step-by-step explanation:

∠BDO = 90°

∠BOD = 30°

∴ ∠DBO = 60°

∠B = ∠C = 60°

∴ ∠EOC = 30°

AO is bisector of BC.

∴ ∠DOE = 120°

∴ ∠AOE = ∠AOD = 60°

Answered by subbareddyram031
0

Answer:

AOE=60

AB=AC AND DOE IS A triangle by sum of all sides in triangle =180 so AOE =60

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