In ∆ABC,AB=AC,O is a point on BC such that BO=CO and OD is perpendicular to AB and OE is perpendicular to AC. if angle BOD=30⁰ then measure of angle AOE is
Answers
Answered by
0
Answer:
angel AOD = 60 DEGREE
Step-by-step explanation:
∠BDO = 90°
∠BOD = 30°
∴ ∠DBO = 60°
∠B = ∠C = 60°
∴ ∠EOC = 30°
AO is bisector of BC.
∴ ∠DOE = 120°
∴ ∠AOE = ∠AOD = 60°
Answered by
0
Answer:
AOE=60
AB=AC AND DOE IS A triangle by sum of all sides in triangle =180 so AOE =60
Similar questions