Question

In △ABC, AB = AC. P is any point on side BC. PM⊥ AB,
P N⊥AC. Prove that (PM + P N) is constant.

Answer 1

Answer:

Step-by-step explanation:

Idk but use a converse BPT theorem

Answer 2

Answer:

From the question it is given that, ABC is a triangle in which AB=AC.

P is a point on the side BC such that PM⊥AB and PN⊥AC.

We have to prove that, BM×NP=CN×MP

Consider the △ABC

AB=AC … [from the question]

∠B=∠C … [angles opposite to equal sides]

Then, consider △BMP and △CNP

∠M=∠N

Therefore, △BMP∼△CNP

So, BM/CN=MP/NP

By cross multiplication we get,

BM×NP=CN×MP