Question

In ∆ABC,
AB = AC = x; BC = 10 cm and the area of the triangle is 60 cm^2. Find x.

Answer 1

Hey Prince,
consult this picture for the diagram
Continuation of Ans:-

h=12cm
As,it is an iso.∆.....So the perpendicular divides the triangle into half
In∆AMC
AC^2=AM^2+MC^2
x^2=12^2+5^2
x^2=144+25=169
x=√169
13 cm....Answer

Answer 2

another method is do it by heron's formula