Question

in ABC, AB=AC=x,BC=10cm and the area ofABC is 60 cm². find x

Answer 1

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Answer 2

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Drop a perpendicular from A to side BC and mark it as D

$= > AD= \sqrt{ {x}^{2} - {5}^{2} }$

$= > area= \frac{1}{2} ×AD×BC$

$= > 60 = \frac{1}{2} \times \sqrt{ {x}^{2} - 25 } \times 10$

$= > 144 = {x}^{2} - 25$

${x}^{2} = 169$

$x = 13cm$

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