Question

in ∆abc ab =bc and angle b=64° find angle c

Answer 1

In ∆ ABC,

AB = BC

•°•

/_A = /_C [ Sides opposite to equal angles are equal. ]

Now,

/_A + /_B + /_C = 180° ( ASP )

/_A + 64° + /_A = 180°

2 /_A = 180° - 64°

2 /_A = 116°

/_A = 58°

So, $<b>/_C = 58°</b>$