In ∆ABC,AB=BC=x and AC=y, then find the area of ∆ABC.
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Step-by-step explanation:
hero's formula,
s=(2x+y)/2
area=√(2x+y)(x+y)(x+y)2x
=√2x(2x+y)(x+y)2
=(x+y)√2x(x+y)
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