in ∆ABC AB is 36 cm AC is 12 cm find BC.
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Given : in ∆ABC AB is 36 cm AC is 12 cm
To Find : Possible values of BC
Solution:
AB = 36 cm
AC = 12 cm
BC = x cm where x > 0
In a triangle sum of any two sides is greater than third side
Hence
AB + AC > BC
AB + BC > AC
BC + AC > AB
AB + AC > BC
=> 36 + 12 > x
=> x < 48
AB + BC > AC
=> 36 + x > 12
True for all values of x
BC + AC > AB
x + 12 > 36
=> x > 24
From all three
24 < x < 48
Hence length of BC is in between 24 and 48 cm
x ∈ (24 , 48 )
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