in∆ABC ,AB perpendicular BC, AB=BC then m angle A=?
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Answer:
In∆ABC
AB is perpendicular BC
so angle B=90⁰
and two sides are equal
AB=BC,so it is issoceles∆
so two angles are also equal
sum of all angle of∆=180⁰
So Angle A=angle C=x
x+x+angle B=180⁰
2x+90⁰=180⁰
2x=180-90
2x=90
x=90/2
x=45⁰
so Angle A=45⁰
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