Question

in∆ABC ,AB²+AC²=50.length of median AD=3.so BC=​

Answer 1

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in triangle ∆ABC , we have to use the theorem of Apolloneous.
we know that,
For AD to be the median, we have,
AB² + AC² = 2(AD² + BD²)
Given, AB² + AC² = 50
⇒ 50 = 2(3² + BD²)
⇒ 50 = 2 (9 + BD² )
⇒ 25 = 9 + BD²
⇒ BD² = 16
⇒ BD = 4
⇒ BC = 2BD = 8

Answer 2

Answer:

8

Step-by-step explanation:

in triangle ∆ABC , we have to use the theorem of Apolloneous.

we know that,

For AD to be the median, we have,

AB² + AC² = 2(AD² + BD²)

Given, AB² + AC² = 50

⇒ 50 = 2(3² + BD²)

⇒ 50 = 2 (9 + BD² )

⇒ 25 = 9 + BD²

⇒ BD² = 16

⇒ BD = 4

⇒ BC = 2BD = 8

∴ Option (c) is correct.