Question

In ∆ABC , AB²+ BC²= AC2²
and in ∆PQR , AngleQ = 90°
and AB = PQ , BC = QR .
Prove: Angle B=90°.​

Answer 1

Answer:

$\huge\purple\star\underline\mathfrak\pink{ANSWER :-}\purple\star$

Step-by-step explanation:

In the given figure ∆ ABC and PQR they are corresponding to each other i.e, if

AB = PQ, BC = QR it can be written as

< ABC = < PQR i.e, 90°

Hence, it is proved that ABC = 90°