In ΔABC,∠ABC=90° , AD=DC, AB=12 cm and BC=6.5 cm. Find the area of ΔADB.
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It is given that ,
In ∆ABC , <ABC = 90° ,
AD = DC ,
AB = 12 cm , BC = 6.5 cm
∆ADB = ( 1/2 )∆ABC
[ Since AD is a median of ∆ABC ]
= ( 1/2 )[ (1/2)× AB × BC ]
= 1/4 × 12 × 6.5
= 19.5 cm²
Therefore ,
Area of ∆ADB = 19.5 cm²
••••
In ∆ABC , <ABC = 90° ,
AD = DC ,
AB = 12 cm , BC = 6.5 cm
∆ADB = ( 1/2 )∆ABC
[ Since AD is a median of ∆ABC ]
= ( 1/2 )[ (1/2)× AB × BC ]
= 1/4 × 12 × 6.5
= 19.5 cm²
Therefore ,
Area of ∆ADB = 19.5 cm²
••••
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