In ∆Abc,∆ABC=90°,AD=DC,AB=12cm & BC = 6.5 cm find the area of ∆ ADB
Answers
Answered by
6
hight=12
base=12
area of a triangle =1/2×base×height
=1/2×12×12
=6×12
=72cm
therefore the area of triangle is 72cm
base=12
area of a triangle =1/2×base×height
=1/2×12×12
=6×12
=72cm
therefore the area of triangle is 72cm
zaheer9849941676:
12 cm
ok bro
Iam sis
then
i love you
my jaan
Brother you this question answer
hey dont say brother
it hurts my heart
Similar questions