In ΔABC,ΔABC, right angled at B, AC=13 cm,B, AC=13 cm, AB=5 cmAB=5 cm then sinA=
Answers
Answered by
1
Answer:
tan30
∘
=
BC
AB
⇒BC=
tan30
∘
AB
BC=5
3
AC
2
=AB
2
+BC
2
AC
2
=5
2
+(5
3
)
2
AC
2
=25+75
AC=10
Hence sides are 5,5
3
,10cm
Answered by
29
Answer:
sin A=10.................
Similar questions