Question

In ABCΔABC, right-angled at BB, AB=5AB=5 and AC=10AC=10, find \angle C∠C.

Answer 1

Answer: Angle C is 30 degrees

Step-by-step explanation:

In ABC

AB = 5

AC = 10 [AC is the hypotenuse ]

Sin Teta = opposite side / hypotenuse

SinC = 5 / 10

Sin C = 1/2

[Since we know that Sin 30 =1/2]

Sin C = Sin 30

[Sin, Sin are cancel ]

Therefore Angle C = 30 degrees