Question

In ABC, AC = 10 cm BC=5 cm AL=6 cm
Find:
(a) area of the Triangle ABC
(b)length of BM

Answer 1

Answer:

(a) 25cm²

(b) 6cm

Step-by-step explanation:

AC = 10cm , BC = 5cm AL = 6cm

In ∆ABC,

Height = 10cm

Base = 5cm

Area of a triangle = 1/2 × height × base

= 1/2 × 10 × 5

= 25cm²

length of BM

Angle L = Angle A

Now BM = AL

BM = 6cm

Answer 2

Answer:

Step-by-step explanation:

in triangle ALC 6^2+ (x+5) ^2= 10^2

(x+5)^2 =100-36=64

(x+5) ^2=8^2

x+5=8

x=8-5=3 =LB

now triangle ALB congruent to triangle BMC

so that AL/AC = BM/BC

6/10=BM /5

BM = 6*5/10= 3 CM

area of triangle = 1/2*base*height

 =1/2*10*3= 15 cm^