In ∆ABC AC=8cm, BC =4cm and height AM =5cm
find
I) the area of ∆ABC
II)Altitude BN
Answers
Answered by
1
Step-by-step explanation:
Given : In △ABC, AB=4 cm and AC=8 cm.
M is the midpoint of BC and AM=3 cm
Using Apollonius theorem,
AB
2
+AC
2
=2(AM
2
+BM
2
)
⟹ 4
2
+8
2
=2(3
2
+BM
2
)
⟹ 16+64=2(9+BM
2
)
⟹ BM
2
=31
⟹ BM=
31
.
∵ BC=2BM
∴ BC=2
31
.
Answered by
0
Answer
Step-by-step explanation:
Soln.
Area of right triangle ABP=1/2×BP×AP
=1/2×2cm×5cm
=5cm sq
Area of right triangle ACP=1/2×PC×AP
=1/2×2cm×5cm
=5cm sq
Area of right triangle ABP+Area of right triangle ACP
=5cm sq+5cm sq
= 10 cm sq
Hence the area of triangle ABC is 10 cm sq
Similar questions