In ∆ABC, AC =AB and ∠ ACB = 90o
, then Prove AB2 = 2AC2
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Answer:
Answer:
Given:
Δ ABC is a right triangle
Also Δ ABC is isosceles
To prove: AB² = 2AC²
Proof:
Here,
hypotenuse = AB
Also, we know that Δabc is isosceles
hence AB = AC (isosceles Δ has two equal sides)
Using Pythagoras theorem in Δ ABC
AB² = AC² + BC²
AB² = AC² +AC² (as AC = BC)
AB² = 2AC².
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