In ABC, AC+BC=28,AB+BC=32 and AC+AB=36. Determine the type of ABC ?
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According to above given data ABC is a scalene triangle.
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AC + BC = 28 (eqn. 1)
AB + BC = 32. (eqn. 2)
AC + AB = 36. (eqn. 3)
Now,
On subtracting eqn. 2 by 1, we get;
AB + BC - AC - BC = 32 - 28
AB - AC = 4. (equ. 4)
Then,
On adding equ. 3 and 4, we get;
AC + AB + AB - AC = 36 + 4
2AB = 40
AB = 20 ut.
Hence, BC = 32 - AB
=> BC = 32 - 20
=> BC = 12 ut.
And, AC = 36 - 20
=> AC = 36 - 20
=> AC = 16 ut.
Therefore,
AB + BC = 32. (eqn. 2)
AC + AB = 36. (eqn. 3)
Now,
On subtracting eqn. 2 by 1, we get;
AB + BC - AC - BC = 32 - 28
AB - AC = 4. (equ. 4)
Then,
On adding equ. 3 and 4, we get;
AC + AB + AB - AC = 36 + 4
2AB = 40
AB = 20 ut.
Hence, BC = 32 - AB
=> BC = 32 - 20
=> BC = 12 ut.
And, AC = 36 - 20
=> AC = 36 - 20
=> AC = 16 ut.
Therefore,
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