In Δ ABC, AC = BC and ∠ C = 110°. Find ∠ A and ∠ B.
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Answer:
GIVEN:
- AC = BC
- ∠ C = 110°
TO FIND:
∠A=?; ∠B=?
SOLUTION:
This is an isosceles triangle because AC = BC.
Thus, the base angles or the angles opposite to the equal sides are equal.
∴∠A=∠B.
Let ∠A=∠B=.
We can use the angle sum property:
∠C+∠B+∠A=180°.
Substitute ∠A=∠B=; ∠C=110°.
++110°=180°.
2=70°
=70°÷2
=35°.
Since ∠A=∠B, ∠A=35°, ∠B=35°.
HOPE THIS HELPS :S
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