Question

In ∆ ABC, ∠ACD is an exterior angle. ∠A= 40,∠B= 45, ∠C= 95 then m∠ACD=?
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Answer 1

Using exterior angle property

∠ACD=∠A+∠B

= 40+45

=85°

THUS, ∠ACD is 85°

HOPE THIS HELPS :D