Question

In ∆ABC, ∠ACD is an exterior angle, if ∠A = 50° and ∠B = 80°, then the measure of ∠ACD is _______​

Answer 1

Answer:

An exterior angle of a triangle is equal to the sum of the opposite interior angles.

Hence, In this case ∠A and ∠B

So,

∠A+∠B=140

∘

as ∠A=∠B

or,2∠A=140

∘

∠A=∠B=70

∘

Step-by-step explanation:

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Answer 2

$\huge\underbrace\mathcal\pink{here \: is \: your \: answer}$

We know that exterior angle of a triangle is equal to the sum of it's opposite interior angle.

So, ∠ACD = ∠A + ∠B

⠀ ⠀⠀⠀⠀⠀= 50° + 80°

⠀ ⠀⠀⠀⠀⠀= 130° ans.

Hope this helps✌✌✌

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