In ΔABC, AD and CE are the bisectors of angle A and angle C respectively. AD and CE intersect at O. If angle ABC = 90 deg, then find angle AOC.
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Angle AOC = exterior angle of triangle AOE
= angle EAO + angle AEO
= A/2 + exterior angle of triangle EBC
= A/2 + B + C/2 = B + (A+B)/2
= 90 + 90/2 = 135 degrees
A+B = 90 as ABC is a right angle triangle
= angle EAO + angle AEO
= A/2 + exterior angle of triangle EBC
= A/2 + B + C/2 = B + (A+B)/2
= 90 + 90/2 = 135 degrees
A+B = 90 as ABC is a right angle triangle
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