Question

In ∆ABC, AD bisects Angle BAC and AD= BC. If Angle BDA= 70°, then calculate Angle ACD and Angle ABD​

Answer 1

Answer:

$\huge\fbox \red{✔An} {\colorbox{crimson}{sw}}\fbox\red{er✔}$

Step-by-step explanation:

In that triangle AD = DC

that means angle DAC =angle DCA=x

Given angle ADB=70°

then angle ADC = 180°-70°=110°(linear pair)

(Linear pair means sum of two angles =180°

Now, we have to find angle ACD

we know that,

sum of all angles in a triangle = 180°

In triangle ACD,

angle ADC+angle DCA+ angle DAC =180°

110°+x+x=180°

110°+2x= 180°