. In △ABC, AD=DB=2.4 cm, AE=3.6cm and AC=7.2 cm. Prove that DE is parallel to BC. If DE =3.5 cm and
BC=5-3, find the value of .
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Given=triangleABC, AD-DB=2.4cm AE=3.6cm and AC =7.2cm Prove that DE is a parallel to BC
We know that,
Step-by-step explanation:
S=a+b+c÷2
S=2.4+3.6+7.2÷2= 6.6
Area of
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