In △ ABC, AD is a median and DE||AB. Prove that BE bisects ∠ B.
Prove with proper format, Given, To prove that, Constructions if required, and Proof.
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Answer:Since AD is the median of ΔABC, then BD = DC.
Step-by-step explanation:
Given,DE || AB and DE is drawn from the mid point of BC i.e.D, then by converse of mid-point theorem,
it bisects the third side which in this case is AC at E.
Therefore, E is the mid point of AC.
Hence, BE is the median of ΔABC.
Hope you understand it.
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