In ΔABC, AD is an altitude and ∠A is right angle. If AB =√20, BD=4, CD = ....,select a proper option (a), (b), (c) or (d) from given options so that the statement becomes correct.
(a) 5
(b) 3
(c) √5
(d) 1
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In the above question we will apply Geometric Mean Theorem.
According to this theorem,
If an altitude divides its hypotenuse in p and q and let length of altitude h.
Then h can be given as following
using above theorem and Pythagoras theorem
we got CD = Q =1
Hence option d is correct
see the attachment
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Answered by
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In ∆ABC ,
<A = 90° , AD = y is the altitude .
AB = √20 , BD = 4
i ) In ∆ADB , <ADB = 90°
By Pythagorean theorem ,
AB² = BD² + AD²
( √20 )² = 4² + y²
20 - 16 = y²
y² = 4
y = 2
ii ) We know that ,
In ∆BAC , <A = 90° ,
D is a point on BC such that
AD perpendicular to BC.
AD² = BD × DC
y² = 4 × x
2² = 4 × x
4/4 = x
x = 1
Therefore ,
x = CD = 1
Option ( d ) is correct.
I hope this helps you.
: )
<A = 90° , AD = y is the altitude .
AB = √20 , BD = 4
i ) In ∆ADB , <ADB = 90°
By Pythagorean theorem ,
AB² = BD² + AD²
( √20 )² = 4² + y²
20 - 16 = y²
y² = 4
y = 2
ii ) We know that ,
In ∆BAC , <A = 90° ,
D is a point on BC such that
AD perpendicular to BC.
AD² = BD × DC
y² = 4 × x
2² = 4 × x
4/4 = x
x = 1
Therefore ,
x = CD = 1
Option ( d ) is correct.
I hope this helps you.
: )
Attachments:
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