In ABC, Ad is the angle bisector of the angle A. If AB=3, AC=6 and BC=33, then AD is:
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In a triangle ABC, AD is the bisector of angle A. If AB =3 AC=6 and BC=3√3. What is the length of AD?
In ∆ABC AD is bisector of angleA
Here AB=3 AC=6 and BC=3√3
Now AB/AC=3/6=1/2
According to angle bisector law BD/DC should be 1/2
Since BC=3√3 therefore BD=√3 and DC=2√3
Then we have BD/DC=√3/2√3=1/2
Again here AB^2 +BC^2=AC^2
Therefor it is a right angle traingle and angle B=90°
Hence from right angle ∆ABD we have
AD^2=AB^2+BD^2
Or, AD^2=(3)^2+(√3)^2
Or, AD^2=9+3
Or, AD^2=12
Or, AD=√12
Or, AD=2√3
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