In ∆ ABC, AD is the median and E is the mid-point of AD. BE is produced meets AC at F. Given AC =9 cm then AF is
a) 4.5 cm b) 6 cm c) 3 cm d) 7.5 cm
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Given:
➨ AD is the median.
➨ E is the mid-point of AD.
➨ BE is produced meets AC at F.
➨ AC = 9 cm
To Find:
➟ AF = ?
Solution:
Draw DG || BF
In ∆BCF,
D is the mid-point of BC.
DG || BG
So, G is the mid-point of FC
⇰ GC = FG
In ∆ADG,
E is the mid-point of AD.
EF || DG
So, F is the mid-point of AG.
⇰ AF = FG
✰ AF = FG = GC
Now, we know that AC = AF + FG + GC
Thus,
AF = 1/3 AC
Value of AC is given = 9 cm ( substitute it's value )
AF = 1/3 × 9
AF = 3 cm
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