Question

In ∆ ABC, AD is the perpendicular bisector of BC (see Fig.). Show that ∆ ABC is an isosceles triangle in AB =AC
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Answer 1

Answer:

here you go

Step-by-step explanation:

to prove = tr. ABC is isosceles

as

BD = DC (AD is perpendicular bisector of BC)

AD = AD (COMMON)

ANGLE ABD = ANGLE ADC = 90 (PERPENDICULAR)

BY SAS :- TRIANGLE ADB IS CONGRUENT TO TRIANGLE ADC

SO AB = AC - BY CPCT

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