Math, asked by shivabiswas55, 2 months ago

In ΔABC, AD is the perpendicular bisector of BC (see the given figure). Show that ΔABC is an isosceles triangle in which AB=AC​

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Answered by JAYANSHI24
1

Answer:

In ∆ABD and ∆DAC

BD = DC (Since AD Perpendicular to BC)

✓ BDA =✓ CDA = 90° (AD perpendicular which makes 90°)

AD=AD (common)

Therefore, ∆ABD congurent∆DAC

AB=AC (by (CPCT)

Hence, proved

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Answered by mehak5213
0

Answer:

given, triangle ABC

and AD is perpendicular bisector of BC

SO, angle ADB = angle ADC = 90°

and BD = DC

by using phythagorean theorem,

AB^2 = AD^2 + BD^2 ( in ADB) - eq.1

AC^2 = AD^2+ DC^2 ( in ADC)

{ BD = DC ,on squaring both side

BD^2 = DC^2 }

AC^2 = AD^2+ BD^2 ( in ADC) - eq. 2

On equating, equation 1 and 2

AB^2 = AC^2

taking square root on both sides,

AB = AC

HENCE, PROVED

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