Question

in ∆ Abc, AD is the perpendicular bisector of BC. Show that ∆ ABC is an isosceles triangle in which AB=AC.​

Answer 1

Answer:

Plz refer the image

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Answer 2

Answer:

below is proved...

Step-by-step explanation:

Given: In A ABC, AD is the perpendicular bisector of BC.

To Prove: A ABC is an isosceles triangle in which AB = AC.

Proof: In A ADB and AADC, ZADB = ZADC |Each = 90° DB = DC

|: AD is the perpendicular bisector of BC

AD = AD | Common

:: ADB = AADC | By SAS Rule

:. AB = ACC.P.C.T.

. AABC is an isosceles triangle in which AB = AC.