Question

in ∆ Abc, AD is the perpendicular bisector of BC. Show that ∆ ABC is an isosceles triangle in which AB=AC.​

Answer 1

Step-by-step explanation:

since ad is a perpendicular bisector of BC

We get BD=DC and /_ADB=ADC=90°

Now,

In triangle ADB and ADC

AD=AD(Common)

ADB= ADC (Given)

BD=DC (Given)

(SASCongruency)

Thus,Ab=Ac

Hence,Teiangle abc is an isoceles triangle.

Hope it helps.

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