In ∆ABC , AD perpendicular BC and AB =AC. If angle BAD = 40° , find angle B nd angle C.
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Answer:
angle B=angle C= 50°
Step-by-step explanation:
In triangle ADB
BAD+ADB+DBA=180° .. (SUM OF ANGLES OF A TRIANGLE)
So
40° +90° +DBA=180°
angle DBA=50°
Similarly
angle DCA=50°
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