Question

In ∆ABC, AD perpendicular on BC, BE perpendicular on AC and AD=BE. Prove that AE=BD.​

Answer 1

Answer:

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Step-by-step explanation:

In △ ABC,

AB = BC = CA,

AD ⊥ BC, BE ⊥ AC,

Proof: in △ ADC and △ BEC

∠ADC = ∠BEC (each 90°)

∠ACD = ∠BCE (common)

and AC = BC (Sides of an equilateral triangle)

∴ △ ADC ≅ △ BEC (A.A.S. Axiom)

Hence,  AD = BE (c.p.c.t)

Hence proved.