In ΔABC and ΔABD, AC = AD, ∠ABC = ∠ABD = 90°,
Prove that ΔABC = ΔABD
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In quadrilateral ABCD, we have AD = BC and
∠DAB = ∠CBA.
In ΔABD and ΔBAC,
AD = BC
[Given]
AB = BA
[Common]
∠DAB = ∠CBA
[Given]
∴ Using SAS criteria, we have ΔABD ≌ ΔBAC
(ii) ∵ ΔABD ≌ ΔBAC
∴ Their corresponding parts are equal.
⇒ BD = AC
(ii) Since ΔABD ≌ ΔBAC
∴ Their corresponding parts are equal.
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answer for the given problem is given
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