In ΔABC and ΔADC, AB = AD and BC = CD. Prove that ∆ABC ≌ ΔADC.
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18
In ΔABC & ΔADC,
AB = AD [given]
BC = CD [given]
AC = AC [common]
So, ∆ABC ≌ ΔADC by SSS criterion.
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triangle ABC is congruent to triangle ADC (by sss congruence)
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