Question

In Δ ABC and D is midpoint of seg BC and AD is a median find. A(ΔBDA) =
A(ΔCDA) ​

Answer 1

$\huge\fbox\red{❥ Question}$

✵ In Δ ABC and D is midpoint of seg BC ⠀⠀and AD is a median find. A(ΔBDA) ⠀⠀A(ΔCDA)

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A(ΔBDA) = A(ΔCDA)

$\fbox\pink{Explanation:}$

✵ This is because a median divides the triangle into two triangles of equal area.

Answer 2

Answer:

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$\huge\rm\underline\purple{Question :-}$

In Δ ABC and D is midpoint of seg BC and AD is a median find.

A(ΔBDA) =A(ΔCDA)

$\huge\rm\underline\purple{Answer :-}$

This is because a median divides a triangle into two triangles of equal area.

HOPE IT HELPS U

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