Question

in ∆ ABC and ∆ def ab =De and <a =<d by SAS axiom which one condition is nessecry to show that ∆ ABC ~ ∆ def​

Answer 1

ANSWER

For triangle to be congruent SAS(Side angle Side) axiom we need to have two equal sides and the included angle same.

In ΔABC and ΔDFE

We have AB=DF

and ∠A=∠D

But ∠A is formed by the two sides AB and AC of ΔABC

But ∠D is formed by the two sides DE and DF of ΔDFE

So we need AC=DE for the two triangles to be congruent.