In ΔABC and ΔDEF , it is being given that: AB = 5 cm, BC = 4 cm and CA = 4.2 cm; DE = 10 cm, EF = 8 cm and FD = 8.4 cm. If AL⊥BC and DM⊥EF, find AL : DM.
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AL: DM is in the ratio 1:2
Step-by-step explanation:
Given: AB = 5 cm, BC = 4 cm and CA = 4.2 cm; DE = 10 cm, EF = 8 cm and FD = 8.4 cm.
AL⊥BC and DM⊥EF
To find: AL:DM
Solution:
Let's find the ratio of the corresponding sides in the two triangles.
AB/DE = 5/10
BC/EF = 4/8
AC/DE = 4.2/8.4
We note that the corresponding sides are all in the same proportion of 1/2.
So ΔABC ~ ΔDEF (SSS similarity)
In ΔABL ~ ΔDEF
∠B = ∠E (corresponding angles)
∠ALB = ∠DME (90 degress)
ΔABL ~ ΔDEF (AA similarity)
So AB/DE = AL/DM (corresponding sides)
5/10 = AL/DM
So AL: DM is in the ratio 1:2
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