In ∆ABC and ∆DEF, it is being given that: AB = 5 cm, BC = 4 cm and CA = 4.2 cm; DE = 10 cm, EF = 8 cm and FD = 8.4 cm. If AL ⊥ BC and DM ⊥ EF, find AL : DM.
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SOLUTION :
Given : AB = 5 cm, BC = 4 cm, CA = 4.2 cm, DE = 10 cm, EF = 8 cm, and FD = 8.4 cm
Since, AB/DE = BC/EF = AC/DF = 1/2
Therefore, ∆ABC ∼DEF (By SSS similarity)
Here, we use the result that in similar triangles the ratio of corresponding altitudes(heights) is same as the ratio of the corresponding sides.
Hence, AL : DM = 1 : 2
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