In ∆ABC and ∆PQR, BC=QR, angle A = 90°, angle B= angle Q = 50° and angle R= 40°. Is ∆ABC=∆POR?
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Answer:
Step-by-step explanation:
Given: In △ABC and △PQR
BC=QR
∠A=90°
∠C=∠R=40°
∠Q=50°
Consider △ABC,
by angle sum property of △
∠A+∠B+∠C=180°
90°+∠B+40°=180°
∠B=180°−130°=50°
Since BC=QR [given]
∠C=∠R=40° [given]
∠Q=∠B=50°
So, △ABC ≅ △PQR [ ASA criteria]
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